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Dear student 
Please find your answer below to the asked query :

 In Mendel's experiment, yellow colour of pea seed was dominant over green colour. 
To determine the genotype of yellow seeded pea plant, test cross is carried out. 
So To distinguish between a homozygous dominant plant (YY) and heterozygous plant (Yy), Mendel bred the unknown yellow pea (Y?) with a green pea, being homozygous recessive (yy). 

So 2 cases are there :
Case 1
When YY  is the genotype of unknown pea plant, then, In this case, the pea has no recessive allele to pass to the offspring. Therefore, 100% of the offspring receive one Y allele and one y allele, making them all yellow.
 
Case 2
When  unknown yellow pea has the genotype Yy, half of the offspring will receive this allele. The other allele will be from the green pea, and will also be a green allele (y). In this case, half of the offspring will produce green peas.

So by progeny of test cross we can determine genotype of yellow seeded pea plant. 

Regards 

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