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Dear Student

Consider the ball when it is at the point P and the string makes an angle θ with vertical. Forces acting on the ball are:

T = tension in the string along its length, and

mg = weight of the particle vertically downward.

Hence, net radial force on the particle is F_R = T - mg cos θ

=> T - mg cos θ = mv²/R

=> T = mv²/R + mg cos θ
So
$T = \frac{m v^{2}}{R} + m g \cos θ T = \frac{50 \times 10^{- 3} \times 1.5 \times 1.5}{0.3} + 50 \times 10^{- 3} \times 10 \times \cos 60 (A s D i a m e t e r = 0.6 m s o R = D / 2) T = 0.375 + 0.25 = 0.625 N$

Regards

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