Ans with solution of the Q which u know
Dear student,
Suppose the mass of Acetic acid (C2H4O2) is x g,
then mass of Oxygen gas O2 is (620-x) g.
Molecular Mass of Acetic acid (C2H4O2) = 60g
Molecular Mass of Oxygen Gas (O2) = 32g
To produce maximum energy,
no. of moles of acetic acid / no. of moles of O2 = 1/2
=> n ( Acetic Acid) * 2 = n( Oxygen) * 1
=> x/60 * 2 = (620 -x)/32 *1
=> (620-x)/x = 16/15
=>(620-x) + 1/x =16/15 + 1
=>620/x = 31/15
=>x = 620 *15 / 31
Mass of acetic acid = x
Suppose Mass of CO2 is (m) gram.
3) Now by observing reaction,
1 / n(Acetic acid) = 2 / n(CO2)
=> n (Acetic acid) * 2 = n(CO2) * 1
=> 2 * x/60 = m / 44
=>m = x*44*2 / 60
=>m = 620 * 15*44*2/31*60 = 440gm
Therefore, mass of CO2 obtained is 440grams.
Regards,
Suppose the mass of Acetic acid (C2H4O2) is x g,
then mass of Oxygen gas O2 is (620-x) g.
Molecular Mass of Acetic acid (C2H4O2) = 60g
Molecular Mass of Oxygen Gas (O2) = 32g
To produce maximum energy,
no. of moles of acetic acid / no. of moles of O2 = 1/2
=> n ( Acetic Acid) * 2 = n( Oxygen) * 1
=> x/60 * 2 = (620 -x)/32 *1
=> (620-x)/x = 16/15
=>(620-x) + 1/x =16/15 + 1
=>620/x = 31/15
=>x = 620 *15 / 31
Mass of acetic acid = x
Suppose Mass of CO2 is (m) gram.
3) Now by observing reaction,
1 / n(Acetic acid) = 2 / n(CO2)
=> n (Acetic acid) * 2 = n(CO2) * 1
=> 2 * x/60 = m / 44
=>m = x*44*2 / 60
=>m = 620 * 15*44*2/31*60 = 440gm
Therefore, mass of CO2 obtained is 440grams.
Regards,