Ans21 Share with your friends Share 0 Ankita Agarwal answered this Dear Student, In ∆AED AE=AD Equal Given So, ∠AED=∠ADE=35° equal angle of equal sidesSo, ∠EAD+∠AED+∠ADE=180°∠EAD=180°-∠AED+∠ADE∠EAD=180°-35°+35°∠EAD=180°-70°∠EAD=110°In ∆ADC and ∆AFB ∠DAC=∠FAB=60° agles of equiletral triaglesNow taking∠EAF+∠FAB+∠BAC+∠DAC+∠EAD=360° center angle of circlex+60°+90°+60°+110°=360°x=360°-320°x=40°hence option B 40° is corrcet Regards 1 View Full Answer Sayani Majumder answered this Option (a) is correct. 0
