Answe for question 2

Dear Student,
given,R=200 ohmI=1Avoltage,V=IR=200×1=200Vpower,P=V×I=200watttotal energy in 5 hours cosumed by the bulb is,E=5×P=5×200=1000 watt h=1kwh
Hope this information will clear your doubts about topic.

If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible.

 
Regards

  • 3
What are you looking for?