Answer 49th question."PLEASE DON'T SEND STHE SIMILAR QUERIES.KINDLY PERFORM THE STEP BY STEP AND APPROPRIATE ANSWER".
Q.49. A man has some hens and cows. If the number of heads be 55 and the number of legs be 160, find the number of hens and the number of cows that the man has.

Let the number of hens = x Let the number of cows = yNow, number of heads = 55x + y = 55      .....1Number of feet = 1602x + 4y = 160x + 2y = 80      .....2Subtracting 1 from 2, we get2y - y = 80 - 55y = 25Put the value of y in 1, we getx + 25 = 55x = 30So, number of  hens = 30Number of cows = 25

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