Answer all 3 questions
Dear Student,
Q3.
Let "n" be the required number of observations.
Σ(x i - 4) = 72, therefore, Σxi - 4n = 72 ....... (1)
And,
Σ(xi - 7) = -3, therefore, Σxi - 7n = -3 ........ (2)
Subtracting the above two equations we get,
3n = 75
n = 25
Q2.
Standard deviation and mean deviation are the two methods of dispersion.
Regards,
Q3.
Let "n" be the required number of observations.
Σ(x i - 4) = 72, therefore, Σxi - 4n = 72 ....... (1)
And,
Σ(xi - 7) = -3, therefore, Σxi - 7n = -3 ........ (2)
Subtracting the above two equations we get,
3n = 75
n = 25
Q2.
Standard deviation and mean deviation are the two methods of dispersion.
Regards,