# Answer fast please

Here in this case from the given data we can write that ,

${f}_{1}={\mu}_{1}{R}_{1}=\frac{1}{5}\times \left(300+200\right)\times 10=1000N\phantom{\rule{0ex}{0ex}}and{f}_{2}={\mu}_{2}{R}_{2}=\frac{1}{4}\times \left(200\right)\times 10=500N\phantom{\rule{0ex}{0ex}}SothehorizontalforceneededtomoveBis,\phantom{\rule{0ex}{0ex}}F={f}_{1}+{f}_{2}=1000+500=1500N\phantom{\rule{0ex}{0ex}}Thusweneededforcemorethan1500NinordertomoveB.\phantom{\rule{0ex}{0ex}}Regards$

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