Answer is B
Dear Student,
At equilibrium, the concentration of A falls from 0.6 molL-1 to 0.3 molL-1 and the concentration of B rises from 0 to 0.6 molL-1 . Thus, 0.3 molL-1 of A on decompoistion gives 0.6 molL-1 of B.
i.e. A = 2B
or, n = 2
Also, from the dimensions i.e. Conc./ Mol. Lit-1 it is clear that the reaction is second order.
Hence, correct answer is (B)
At equilibrium, the concentration of A falls from 0.6 molL-1 to 0.3 molL-1 and the concentration of B rises from 0 to 0.6 molL-1 . Thus, 0.3 molL-1 of A on decompoistion gives 0.6 molL-1 of B.
i.e. A = 2B
or, n = 2
Also, from the dimensions i.e. Conc./ Mol. Lit-1 it is clear that the reaction is second order.
Hence, correct answer is (B)