answer please of this question

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let the point of intersection by line l be O on AB
we know that line l is the perpendicular bisector so
Given:AB is a segment and l is a perpendicular bisector such that AO=BO and AOP=BOP=90
To prove:P is equidistant from point A and B
Proof:
AO=OB(given)
POA=POB (each = 90 degrees) (given)
PO=PO (common)
by SAS congurence Triangle AOP = TriangleBOP
PA = PB (CPCT)
Hence P is equidistant from point A and B
 
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