Answer pls thermodynamics
Solution
The standard free energy change can be calculated as follows:
∆G0 = −2.303RTlogKc
T = 0oC = 273 K
Putting the given values, we get
∆G0 = −2.303×8.314×273×log(1.657×10−5)
∆G0 = +24989.4 J
Since the value of standard free energy change is positive, the forward reaction is non-spontaneous.
Thus, the backward reaction will be spontaneous.
The standard free energy change can be calculated as follows:
∆G0 = −2.303RTlogKc
T = 0oC = 273 K
Putting the given values, we get
∆G0 = −2.303×8.314×273×log(1.657×10−5)
∆G0 = +24989.4 J
Since the value of standard free energy change is positive, the forward reaction is non-spontaneous.
Thus, the backward reaction will be spontaneous.