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In the polar protic solvent, the increasing order of nucleophilicity is I- > Br- > F-.
Iodide ion has a large size and weak conjugate base of HI. The iodide ion is least hydrated due to less charge density. Hence, it can easily attack an electrophilic site.
In the case of fluoride ions, the negative charge is on small fluoride ions and is a weak conjugate base of HF. Due to its small size and high charge density, it is heavily hydrated hence cannot attack the electrophilic site.
In polar protic solvent, basicity anti parallels nucleophilicity.
Option C is correct
Regards
In the polar protic solvent, the increasing order of nucleophilicity is I- > Br- > F-.
Iodide ion has a large size and weak conjugate base of HI. The iodide ion is least hydrated due to less charge density. Hence, it can easily attack an electrophilic site.
In the case of fluoride ions, the negative charge is on small fluoride ions and is a weak conjugate base of HF. Due to its small size and high charge density, it is heavily hydrated hence cannot attack the electrophilic site.
In polar protic solvent, basicity anti parallels nucleophilicity.
Option C is correct
Regards