Answer question 11 fastttt
Dear Student,
Given,
mass if bullet m1 = 50 g = 0.05 Kg
velocity of bullet v1 = 35 m/s
mass if rifle m2 = x Kg
velocity of recoil v2 = 350 cm/s = 3.5 m/s
before firing, both gun and rifle are at rest so,
total momentum before firing = 0
Acc to the conservation of momentum
Total momentum before firing = Total momentum after firing
Total momentum after firing = 0
m1v1 + m2v2 = 0
0.05 × 35 + x × (-3.5) = 0 (as recoil is in opposite direction -ve sign is taken)
1.75 - 3.5x = 0
x = -1.75/-3.5
x = 0.5 Kg
Therefore, the mass of the rifle is 0.5 Kg.
Hope this information will clear your doubts about the topic.
If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible.
Regards
Given,
mass if bullet m1 = 50 g = 0.05 Kg
velocity of bullet v1 = 35 m/s
mass if rifle m2 = x Kg
velocity of recoil v2 = 350 cm/s = 3.5 m/s
before firing, both gun and rifle are at rest so,
total momentum before firing = 0
Acc to the conservation of momentum
Total momentum before firing = Total momentum after firing
Total momentum after firing = 0
m1v1 + m2v2 = 0
0.05 × 35 + x × (-3.5) = 0 (as recoil is in opposite direction -ve sign is taken)
1.75 - 3.5x = 0
x = -1.75/-3.5
x = 0.5 Kg
Therefore, the mass of the rifle is 0.5 Kg.
Hope this information will clear your doubts about the topic.
If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible.
Regards