Answer question no.15...... Q15. AD is altitude of an isosceles triangle ABC is which AB = AC = 30 cm and BC = 36 cm. A point O is marked on AD in such a way for ∠ BOC = 90°. Find the area of quadrilateral ABOC. Share with your friends Share 0 Yash Kunjeer answered this i dont know -3 View Full Answer
