Answer the 23rd question

Dear Student

Given:
Current, I = 1 A
Time, t = 1 s
Using the formula:
$$\begin{gathered} I\mathit{=}\frac{\mathit{Q}}{\mathit{t}} \\ \mathrm{or}, \\ Q\mathit{=}I\mathit{\times }t \\ =1\times 1 \\ =1 \mathrm{C} \end{gathered}$$
Now, if the charge is $1.6\times {10}^{-19}\mathrm{C}$, the number of electrons is 1.
So, if the charge is 1 C, the number of electrons is given by:

$\frac{1}{1.6\times {10}^{-19}}\times 1=6.25\times {10}^{18}$
Thus, $6.25\times {10}^{18}$electrons should pass through a conductor in 1 second to constitute 1 ampere current.

Regards