Answer the 37the question "DON'T SEND STHE SIMILAR QUERIES KINDLY PERFORM THE STEP BY STEP AND APPROPRIATE ANSWER" Q - Maths - Congruency of Triangles

Question

Answer the 37the question "DON'T SEND STHE SIMILAR QUERIES KINDLY
PERFORM THE STEP BY STEP AND APPROPRIATE ANSWER"
Q 37 In the adjoining figure, AB || DC CE and DE bisects ∠ B
C D   a n d   ∠ A D C respectively Prove that AB =
AD + BC

Muskaan Talwar · Accepted Answer

Dear Student,

CE bisects ∠BCD⇒∠BCE=∠DCE=∠1sayDE bisects ∠ADC⇒∠ADE=∠CDE=∠2sayNow AB∥DC and CE is transversal⇒∠CEB=∠DCE=∠1  alternate anglesAlso AB∥DC and DE is transversal⇒∠AED=∠CDE=∠2  alternate anglesIn △ADE,∠ADE=∠AED=∠2Thus, AE=AD sides opposite to equal angles are equalIn △BCE,∠BCE=∠CEB=∠1Thus, BE=BC sides opposite to equal angles are equalNow, AE=AD and BE=BC⇒AE+BE=AD+BC⇒AB=AD+BC

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Answer the 37the question."DON'T SEND STHE SIMILAR QUERIES.KINDLY PERFORM THE STEP BY STEP AND APPROPRIATE ANSWER". Q.37. In the adjoining figure, AB || DC. CE and DE bisects ∠ B C D a n d ∠ A D C respectively. Prove that AB = AD + BC.

Answer the 37the question."DON'T SEND STHE SIMILAR QUERIES.KINDLY PERFORM THE STEP BY STEP AND APPROPRIATE ANSWER".
Q.37. In the adjoining figure, AB || DC. CE and DE bisects $∠ B C D a n d ∠ A D C$ respectively. Prove that AB = AD + BC.