Answer the 9 (i) question. { NO LINKS }.{ NO ANSWERS FROM GOOGLE }. Q.9 (i) If the lengths of the sides of a triangle are in the ratio 3 : 4 : 5 and its perimeter is 48 cm, find its area. Share with your friends Share 0 Varun Rawat answered this 9. i.Let ABC be the ∆.Let a = BC = 3x cm; b = CA = 4x cm; c = AB = 5x cmNow, perimeter of ∆ABC = 48 cm⇒a + b + c = 48⇒3x + 4x + 5x = 48⇒12x = 48⇒x = 4So, a = 3×4 = 12 cm; b = 4×4 = 16 cm; c = 5×4 = 20 cmNow, semi-perimeter, s = 482 = 24 cmarea of ∆ABC = ss-as-bs-c=2424-1224-1624-20=24×12×8×4=9216=96 cm2 2 View Full Answer