Answer the following questions. Share with your friends Share 0 Vipra Mishra answered this Dear Student L.C. = 0.01 mmMeasure value = 1 mmNumber of divisions = 27Thus total reading = Measured value +number of division×Least CountReading = 1 mm +0.01×27 = 1+0.27 = 1.27 mmHence the diameter of wire is 1.27 mm = 0.127 cmNow when the zero error is +0.005 cmMeans when the masrl is at zero, the actual reading is 0.005cmSo, the actual value of diameter of wire = 0.127 -0.005cm = 0.122 cm Regards 0 View Full Answer