Dear student, Now replacing a by 2L, we have B=9μ0i4πL Option 1 is correct Regards

Answer the following

Answer the following current c is 5vß times the magnetic induction at a point on its axis. The distance of the point from the centre of the coil in cm is 2) 10 3) 20 4) 25 27 The magnetic field at the centre of an equilaterial triangular loop of side 2L and earning a current 'i' is 3goi 4) 4zL 4zL 47tL

Dear student,

Now replacing a by 2L, we have

B = \frac{9 μ_{0} i}{4 π L}

Option 1 is correct
Regards