Answer the given question:

Q. The last three digits in 10 ! are 
(A) 800 
(B) 700 
(C) 500
(D) 600 

Dear Student,



Last three digits of 10!

=10!
=1×2×3×4×5×6×7×8×9×10
=(1)×(2×5)×(3×4×6×7×8×9)×10
={3×(2×2)×(2×3)×7×(2×2×2)×(3×3)}×100
=3⁴×2⁶×7×100
=81×64×7×100

So, for last three digits of 10!
=1 × 4 × 7 × 100 {Where 1 from 81 and 4 from 64}
=800  {where 1×4×7=28 but only 8 is taken for last digit}


So, answer will be 800


Regards