Answer the question
Dear Student,
Answer 21
Correct option is B)
Reason: P on treatment with acidified KMnO4 will convert both -OH and -CHO to -COOH (Q)
P on treatment with hot copper will convert -OH to -CHO (R)
Both Q and R will be optically inactive.
As only this compound gives positive Tollen's reagent test. So, it must have aldehyde.
This aldehyde would be converted to acid in S and will be optically active.
Answer 22)
As there is one chiral carbon in P.
So, number of stereoisomers will be 2.
Option A is correct.
Regards
Answer 21
Correct option is B)
Reason: P on treatment with acidified KMnO4 will convert both -OH and -CHO to -COOH (Q)
P on treatment with hot copper will convert -OH to -CHO (R)
Both Q and R will be optically inactive.
As only this compound gives positive Tollen's reagent test. So, it must have aldehyde.
This aldehyde would be converted to acid in S and will be optically active.
Answer 22)
As there is one chiral carbon in P.
So, number of stereoisomers will be 2.
Option A is correct.
Regards