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x^3+x^2-4x-4 =x^2(x+1)-4(x+1) =(x^2-4)(x+1) =(x+2)(x-2)(x+1) If x^3+x^2-4x-4 =0 then (x+2)(x-2)(x+1)=0 => x=-2,2,-1
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[x square - 2] [x+1] [x-1]
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