Answer these questions given below Share with your friends Share 0 Shruti Tyagi answered this Dear student, Given: ∠ABE=120°∠ECD=100°AB∥CDNow, ∠ABE+∠FEB=180° --[int. angles on same side of transversal]⇒120°+∠FEB=180°⇒∠FEB=60°Now, ∠DCE=∠CEF --[alt int. angles]⇒100°=x+∠FEB⇒100°=x+60°⇒x=40° Regards 0 View Full Answer
