Answer this questtion Share with your friends Share 0 Rohit Babu answered this Dear Student, The formula for maximum permissible speed of the car on a banked circular roadat 9° is given by, v2 = rgtanθ+μ1-μtanθ----1 we are given v= 40m/s, and v=2πrtor r=v t2π=40×2×7×602×22=840011m.now putting all these values in eqn 1 to find the value of μ. Thus 40×40 = 8400×10tan9°+μ11×1-μ×tan9°or 1600 = 840000.1584+μ111-0.1584μor 22105=0.1584+μ1-0.1584μor 22-22×0.1584μ=105×0.1584+105μor 108.4848μ=5.37or μ = 5.37108.4848=0.05 Regards.. 0 View Full Answer