# Answer to the 36th question."DON'T SEND STHE SIMILAR QUERIES.KINDLY PERFORM THE STEP BY STEP AND APPROPRIATE ANSWER". Q.36. In the adjoining figure, AB = AC, D is a point in the interior of $△$ ABC such that $\angle$ DBC = $\angle$ DCB. Prove that AD bisects $\angle$ BAC of $△$ ABC.

draw a triangle abc with point d somewhere in the centre. join db, dc and da

B and C are the bases of ur triangle.... u should get a triangle dbc insode the original triangle abc

GIVEN: ab = ac, angle dbc = dcb

PROOF: given angle dbc = dcb

Therefore DB = DC [sides opp. equal angles of a triangle]

Consider Triangles ABD, ACD

AB = AC [given]