Answer very fast
In the adjoining figure, AB = AC, P and Q are points on BA and CA respectively such that AP=AQ. Prove that
(i) ∆APC ≌ ∆AQB
(ii) CP = BQ
(iii) ∠ACP = ∠ABQ.
Dear student, In triangle ADB and triangle BCA AD=BC (GIVEN) DB=CA (GIVEN) angleDAB=angleABC (ANGLES OPPOSITE TO EQUAL SIDES ARE ALSO EQUAL) SO,TRIANGLE ADB CONGRUENT TO TRIANGLE BCA (SAS) SO,angle ADB=angleBCA (CPCT) ALSO, angle DAB =angleCBA (CPCT) Regards