Any method to crack this qn
Dear Student,
Option 4 is correct.
There is a 30% crossing over of A and B present on the same chromosome that means the probability of occurring of crossing over is 30/100 that is 0.3
Now if the cell has genotype AB/ab in cis arrangement then it has four types of gametes i.e AB, Ab, aB, ab. In which two gametes are of the recombinant type and the other is of the parental type.
Considering aB as recombinant gamete of the plant having genotype Aa Bb is cis arrangement, therefore the probability of occurrence of aB is 1/2 i.e 50% or 0.5 Hence, the percent of gamete aB formed is 0.3 X 0.5 that is 1.5 So, the probability is 1.5 that is 15%.
Regards.
Option 4 is correct.
There is a 30% crossing over of A and B present on the same chromosome that means the probability of occurring of crossing over is 30/100 that is 0.3
Now if the cell has genotype AB/ab in cis arrangement then it has four types of gametes i.e AB, Ab, aB, ab. In which two gametes are of the recombinant type and the other is of the parental type.
Considering aB as recombinant gamete of the plant having genotype Aa Bb is cis arrangement, therefore the probability of occurrence of aB is 1/2 i.e 50% or 0.5 Hence, the percent of gamete aB formed is 0.3 X 0.5 that is 1.5 So, the probability is 1.5 that is 15%.
Regards.