Anyone can tell me howto cunsruct a triangle by making some arc??

Dear Student,

Please find below the solution to the asked query :


Consider the following example.

Suppose we have to draw a triangle XYZ, in which XY = 6 cm; YZ = 7 cm; XZ = 5 cm.

Here is the answer.



$$\begin{gathered} \mathrm{Given}: \mathrm{In} ∆\mathrm{XYZ}, \mathrm{XY}= 6 \mathrm{cm}, \mathrm{YZ}=7 \mathrm{cm} \mathrm{and} \mathrm{XZ}=5 \mathrm{cm} \\ \mathrm{To} \mathrm{construct}: ∆\mathrm{XYZ} \\ \mathrm{Steps} \mathrm{of} \mathrm{construction}: \\ 1. \mathrm{Draw} \mathrm{a} \mathrm{line} \mathrm{segment} \mathrm{XY}=6 \mathrm{cm}. \\ 2. \mathrm{With} \mathrm{X} \mathrm{as} \mathrm{centre} \mathrm{and} \mathrm{radius} 5 \mathrm{cm}, \mathrm{draw} \mathrm{an} \mathrm{arc}. \\ 3. \mathrm{Again}, \mathrm{with} \mathrm{Y} \mathrm{as} \mathrm{centre} \mathrm{and} \mathrm{radius} 7 \mathrm{cm}, \mathrm{draw} \mathrm{another} \mathrm{arc} \mathrm{to} \mathrm{cut} \mathrm{the} \mathrm{arc} \\ \mathrm{of} \mathrm{step} 2 \mathrm{at} \mathrm{point} \mathrm{Z}. \\ 4. \mathrm{Join} \mathrm{XZ} \mathrm{and} \mathrm{YZ}. \\ \mathrm{Hence}, \mathrm{XYZ} \mathrm{is} \mathrm{the} \mathrm{required} \mathrm{triangle}. \end{gathered}$$

Hope this would clear your doubt.

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