are there chances of leakage of impulse in non-myelinated neurons everytime since there is no myelin sheath present?

Dear Student.
Please find below the solution to the asked query.

There is no chance of leakage of impulse in non-myelinated neurons. In fact role of the myelin sheath is not to prevent leakage.
The insulated sheath that surrounds the core of the nerve fibre or the axon of the neuron is called myelin sheath. It consists of the fat-containing cells called the Schumann cells and helps in the fast transmission of nerve impulse.

The electric signals are transmitted from one neuron to next and to the muscles across a synapse through the release of chemicals called neurotransmitters. The axon terminal of nerve fibres contain synaptic vesicles filled with these neurotransmitters which are released in the gap called synapse. The released neurotransmitters reach to the next neuron causing changes over their and start a similar electrical impulse in a dendrite of the next neuron or action in the muscle.

Observe the flow diagram given below

 

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The diagram shows propagation of nerve impulses from one neuron to next and then from a neuron to muscle. 

the first picture shows the propagation of nerve impulses from dendrite of one neuron to axon of the next.

the second picture shows the location of synapse and third and fourth illustrates the synapse.

Hope this information will clear your doubts about the topic.
If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible.
Regards.

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