Arrange the solutes a, b, c and d in decreasing order of amount of solute precipitated when their respective hot saturated solutions are cooled from 100°C to 30°C. Below given table shows the amount of solute in grams dissolved in same amount of water at different temperatures.
| 30°C | 60°C | 100°C | |
| (a) | 120 | 140 | 160 |
| (b) | 130 | 120 | 150 |
| (c) | 125 | 130 | 140 |
| (d) | 130 | 135 | 140 |
Dear student,
The amount of precipitate for the case (a) will be (160-140) + (140-120) = 40g
The amount of precipitate for the case (b) will be (150-120) + (no precipitate aftert that) = 30g
The amount of precipitate for the case (c) will be (140-130) + (130-125) = 15g
The amount of precipitate for the case (d) will be (140-135) + (135-130) = 10g
Hence the decreasing order must be
a>b>c>d
Hope this helps,
Regards
The amount of precipitate for the case (a) will be (160-140) + (140-120) = 40g
The amount of precipitate for the case (b) will be (150-120) + (no precipitate aftert that) = 30g
The amount of precipitate for the case (c) will be (140-130) + (130-125) = 15g
The amount of precipitate for the case (d) will be (140-135) + (135-130) = 10g
Hence the decreasing order must be
a>b>c>d
Hope this helps,
Regards