"Arvind has an ore of a very less reactive metal. He heats it strongly in air for a long time.

What should Arvind do next in order to obtain pure metal?

  • A)

    Roasting

  • B)

    Calcination

  • C)

    Electrolytic refining

  • D)

    Electrolytic reduction

25.00% got it right!Answer:CSolution:

When ores of less reactive metals are heated in the presence of air, they form their respective oxides. This process is known as roasting. On further heating, these metal oxides get converted to metal. Now, the only thing that has to be done to obtain pure metal is to purify the metal obtained after heating. This can be done by electrolytic refining. Hence, to obtain pure metal, Arvind will carry out electrolytic refining of the metal.

The correct answer is C.

Why alternative A is wrong:

Roasting is usually done for changing the sulphide ores into their respective oxides. In this process, an ore is heated in the presence of oxygen.

Why alternative B is wrong:

Calcination is done for changing the carbonate ores to their respective oxides. In this process of calcination, heating is done in the absence of oxygen.

Why alternative D is wrong:

The oxides of highly reactive metals are very difficult to reduce. The process of electrolytic reduction is usually used for doing this"

I don't understand the reason for ans D bcoz here its given that highly reactive metals are difficult to reduce but in question it is less reactive metal????

Electrolytic reduction is carried out for highly reactive metals whose oxides are difficult to be reduced. 
And we have a very less reactive metal which can be reduced easily thus there is no need of electrolytic reduction in Arvind's case.
i guess you will understand now and let us know for further query in this question.

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