at 1 atmosphere pressure and 27⁰​C temperature volume of balloon filled with gas is 500ml. the stretching capacity of balloon is 3 times the volume of gas at one atmosphere.then the temperature above which balloon bursts.

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Please find the solution to the asked query:

$$\begin{gathered} Given T_1 ={27}^{o}C = 273+27 =300K \\ Initial volume V_1 =500mL \\ Final volume V_2= 3 times the volume of the gas \\ =3\times 500 =1500mL \\ {T}_2=? \\ From Charles Law \\ \frac{V_1}{T_1}=\frac{V_2}{T_2} \\ \frac{500}{300}=\frac{1500}{T_2} \\ {T}_2 =900K \end{gathered}$$
T₂= 627^oC

Thus the balloon will not burst until the temperature is below 627^oC and will only burst once this temperature is crossed



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