At one end A of a diameter AB of a circle of radius 5 cm, tangent XAY is drawn to the

circle. The length of the chord CD parallel to XY and at a distance 8 cm from A is

Here is the solution to your question

We have AM = 8cm

So, OM = AM - OM

 =8-5

 = 3 cm

Since OM is perpendicular to the chord CD.

So in triangle OCM apply Pythagoras Theorem to get,

Hence CD= 2 CM

 = 8 cm

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