At one end A of a diameter AB of a circle of radius 5 cm, tangent XAY is drawn to the
circle. The length of the chord CD parallel to XY and at a distance 8 cm from A is
Here is the solution to your question
We have AM = 8cm
So, OM = AM - OM
=8-5
= 3 cm
Since OM is perpendicular to the chord CD.
So in triangle OCM apply Pythagoras Theorem to get,
Hence CD= 2 CM
= 8 cm