At the end of the winter season, a shopkeeper earns a profit of Rs 100 by selling a shirt but incurred a loss of Rs 50 on selling a woollen jacket. At the end of sale on one day, he incurred a loss of Rs 200 while he sold 10 jackets. How many shirts did he sell on that day?

Given :

Profit earned by selling a shirt =Rs.100

The loss incurred by selling a Woollen jacket =Rs.50

Total loss incurred at the end of the day =Rs.200

Number of jackets sold =10

To find :

We have to find the number of jackets he sold on the day.

Solution :

Loss incurred by selling jackets =Rs.10×50=Rs.500

Let the number of shirts sold be p.

Profit earned by selling p shirts =Rs.p×100=Rs.100p.

Therefore,

Rs.500−Rs.100p=Rs.200

100p=500−200

100p=300

$p =\frac{300}{100}$

p=3.

Therefore, the number of shirts sold on that day is 3.


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