At what temperature will a given volume of a gas at 0 degree Celsius become double its volume at constant pressure?

Given : 
 Temperature , T_1​ = 0^o C or 273 K

​Solution :
Condition 1 : T_​1 = 273 K ; volume = V₁ ; pressure = P
ideal gas equeation for this equation  
PV₁ = nRT₁
PV₁ = nR$\times$273         .............. 1)
Condition 2 : T₂ = ?  ; volume = 2V₁  ; pressure = P (constant) 
Ideal gas equation for this equation 
P$\times$2V₁ = nRT₂        ................2)  
Divide the equation 1 with 2
$\frac{P\times V_1}{P\times 2V_1} = \frac{nR\times 273}{nR\times T_2}$
 $\frac{1}{2} = \frac{273}{T_2}$ 
T₂ = 273 $\times$2 =   546 K
At 546 K the volume will be doubled .