Attempt question no 12 after reading passage - Science - Motion

Question

Attempt question no 12 after reading passage

PASSAGE -IV

A thief is running on a motorcycle at a constant speed of 25
ms–1 A police jeep starts chasing from a point 1 25 km behind
him a uniform acceleration of 2 ms–2

Q12 What should be the minimum acceleration of the thief to escape
from police

(A) 1 ms–2 (b) 1 25 ms–2

(C) 1 5 ms–2 (d) 1 75 ms–2

Pintu B. · Accepted Answer

Dear Student ,
Here in this case , the thief is moving with constant speed 25
m/s
Now the policeman starts chasing from 1 25 km behind him and with
acceleration of 2 m/s2
So from the equation of motion time taken by the policeman to reach the thief is ,S+ut=12at2or , 1250+25t=12×2×t2or, t2-25t-1250=0or, t2-50t+25t-1250=0or , t-50t+25=0or,t=50 sSo velocity of the police=v=u+at=0+2×50=100 m/sSo , the minimum acceleartion of the thief to escape from police is ,amin=100-2550=7550=32=1
5 m/s2
Regards