(b+c)x2-(a+b+c)x+a=0

Dear student,

b+cx2-a+b+cx+a=0D=a+b+c2-4b+ca=a2+b2+c2-2ab+2bc-2ca=a-b-c2x=a+b+c±a-b-c22b+c=a+b+c±a-b-c2b+cx=ab+cor 1

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  • 11
(bc)x^2 - (abc)xa=0
bcx^2 - abcxa=0
bcx(x-a^2)=0
bcx=0 ; x-a^2=0
x=0. ; x=a^2
  • -1
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