BARRIERS ARE PLACE AROUND TREES. FOR EACH INCH OF TRUNK DIAMETER, THE PROTECTION ZONE SHOULD HAVE A RADIUS OF 4/3 FEET. FIND THE AREA OF THE ZONE FOR A TREE WITH A TRUNK CIRCUMFERENCE OF 63 INCHES.
circumference = 2(pi) r = 63 inch
i.e r = 63/2(pi) = 10.0
Protection Zone = 4/3 feet = 16 inch
Now the radius of protection zone will be R = 10 +16 = 26 inch
Area of Total zone = 2(pi)26 = 163.28 inch 2
Hope this would have cleared your doubt .
i.e r = 63/2(pi) = 10.0
Protection Zone = 4/3 feet = 16 inch
Now the radius of protection zone will be R = 10 +16 = 26 inch
Area of Total zone = 2(pi)26 = 163.28 inch 2
Hope this would have cleared your doubt .