Be+3 and a proton are accelerated by the same potential their de Broglie wavelengths are in ratio of??

Dear student
Please find the solution to the asked query:
Charge of proton =emass of proton =uCharge of Be3+ =3emass of Be particle =4uDe broglie wavelength is given by:λ =hmvthe momentum acquired by proton =2ueVthus λproton =h2ueVfor Be3+ particle:λ Be3+ =h2×4u×3e×VThen ,λproton λ Be3+=h2ueVh2×4u×3e×V=123

Hope this information will clear your doubts regarding the topic. If you have any other doubts please ask here on the forum and our experts will try to solve them as soon as possible.

  • -25
What are you looking for?