Be+3 and a proton are accelerated by the same potential their de Broglie wavelengths are in ratio of??

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Please find the solution to the asked query:
Charge of proton =emass of proton =uCharge of Be3+ =3emass of Be particle =4uDe broglie wavelength is given by:λ =hmvthe momentum acquired by proton =2ueVthus λproton =h2ueVfor Be3+ particle:λ Be3+ =h2×4u×3e×VThen ,λproton λ Be3+=h2ueVh2×4u×3e×V=123

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