Bob wants to cover the floor of a room 3m wide and 4.5m long by squared tiles. If each square tile is of side 0.75m,find the cost of flooring the room at the rate of ₹4.50 per tile. Please answer fast , test soon.

Length of the floor of a room = 4.5 m
And width of the floor of a room = 3 m
So area of the floor of a room = $4.5 \mathrm{m}\times 3 \mathrm{m} = 13.5 {\mathrm{m}}^2$
Now side of each square tile = 0.75 m
So area of each square tile = ${\left(0.75 \mathrm{m}\right)}^2 = 0.;5625 {\mathrm{m}}^2$
So total number of square tiles needed to cover the floor = $\frac{\mathrm{area} \mathrm{of} \mathrm{the} \mathrm{floor}}{\mathrm{are} \mathrm{of} \mathrm{each} \mathrm{square} \mathrm{tile}} = \frac{13.5}{0.5625} = 24$
Cost each tile = Rs.4.50
So total cost of flooring the room = $24\times 4.50$ = Rs.108