Boron has two isotopes B10 and B11 whose relative abundances are 20% and 80% respecctivly. Atomic weight of Boron is :A) 10B)11C)10.5D)10.8please show the answer with method

Average atomic mass = sum of product of relative abundance and atomic mass of isotopes.

Average atomic mass of boron =

= (10 x 20/100) + (11 x 80/100)

= 2 + 8.8

= 10.8 u

 

Hence, option D) is correct

 

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