By what measure the angle dcy is constructed on side c pls explain properly
Dear Student,
Step I: Draw a line segment BC of 7 cm. At point B, draw an angle of 75°, say ∠XBC.
Step I: Draw a line segment BC of 7 cm. At point B, draw an angle of 75°, say ∠XBC.
Step II: Cut a line segment BD = 13 cm (that is equal to AB + AC) from the ray BX.
Step III: Join DC and make an angle DCY equal to ∠BDC.
Step IV: Let CY intersect BX at A. ΔABC is the required triangle.
Therefore, According to your query, the angle of DCY is equal to angle BDC.
Regards