from an external point p, two tangents pa and pb are drawn to the circle c(o,r). if op=2r show that the triangle apb is equilateral.

AP is the tangent to the circle.

∴ OA ⊥ AP  (Radius is perpendicular to the tangent at the point of contact)

⇒ ∠ OAP = 90º 

In Δ OAP,

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