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(c) The cross-section of a canal is shown in figure (iii) given below. If the canal is 8 m wide at the top and 6 m wide at the bottom and the area of the cross-section is 16.8 m^{2}, calculate its depth.

$Areaoftrapezium=Halfthesumofparallelsides\times Perpendiculardis\mathrm{tan}cebetwwentheparallelsides\phantom{\rule{0ex}{0ex}}\phantom{\rule{0ex}{0ex}}Areaoftrapezium=16.8{m}^{2}\phantom{\rule{0ex}{0ex}}16.8=\frac{1}{2}\times \left(8+6\right)\times h\phantom{\rule{0ex}{0ex}}16.8=\frac{1}{2}\times 14\times h\phantom{\rule{0ex}{0ex}}\phantom{\rule{0ex}{0ex}}16.8=7\times h\phantom{\rule{0ex}{0ex}}\phantom{\rule{0ex}{0ex}}h=\frac{16.8}{7}=2.4m$

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