Caculate the emf of the cell in which the following reaction takes place :
Ni(s) + 2Ag+ (0.002 M) ----- Ni2+ (0.160 M) + 2Ag(s)
Given that E0 (cell) = 1.05 V.
Solution:
Given that
[Ag+] = 0.002 M
[Ni+2] =0.160 M
n = 2
Apply the Nernst equation:
Substituting the values, we get
