Calculate cell potential of the following cell

Zn(s) | Zn2+ || Pb2+ | Pb(s)

Given E Pb/Pb2+ =+0.12V, E Zn/Zn2+ =+0.76V

Half cell reactions for the given cell:
Zn Zn2+ + 2ePb2+ + 2e Pb 

Ecell = oxidation potential + reduction potentialEcell0 =EZn/Zn2+ 0 + EPb2+/Pb0       =0.76 +(-0.12)       =0.64 V

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