calculate standard enthalpy of formation of carbon disulphide . given that the standard enthalpy of combustion of C,S and CS2 are -393.3 , -293.72 , -1108.76 KJ mol respectively

CS2 +3O2  CO2 + 2SO2   H= - 1108.76 kJ mol-1C +O2  CO2          H= - 393.3 kJ mol-1S +O2  SO2          H= - 293.72 kJ mol-1H= HP - HR     = HCO20 + HSO20 - HCS20 + 3 HO20- 1108.76 = - 393.3 + (- 293.72) - HCS20    (since enthalpy of formation of oxygen = 0)HCS20  = - 393.3 + (- 293.72) + 1108.76     = 421.74 kJ/mol

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