calculate the amount of heat required to convert 200g of ice at -10°C into water at 10°C

Heat required to convert ice at -10oC to ice at 0oC:Q1=mct =200×0.5×10 =1000 calHeat required to convert ice at 0oC to water at 0oC:Q2=mL =200×80 =1600 calHeat required to convert water at 0oC to water at 10oC:Q3=mct =200×1×10 =2000 calTotal heat required to convert ice at -10oC to water at 10oC:Q=Q1+Q2+Q3 =4600 cal

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