calculate the charge in internal energy when a gas expands from 0.3 dm3 to 1.5 dm3 against a constant pressure of 20 kilopascal after gaining 2.67 kj of heat? Share with your friends Share 0 Vartika Jain answered this Dear Student, W=-P∆VP= 20 kPa= 20×103 Pa ∆V=V2-V1= 1.5dm3-0.3 dm3= 1.2 dm3 W= -(20×103 Pa)(1.2 dm3 )×m31000=-24 JNow, q= +2.67 kJAccording to first law of thermodynamics∆U=q+Wor,∆ U=2.67×103+(-24 J) =2646 J 1 View Full Answer
