Calculate the components of a vector of magnitude unity which is at right angles to the vectors 2i + j - Maths - Vector Algebra

Question

Calculate the components of a vector of magnitude unity which is at
right angles to the vectors 2i + j - 4k and 3i + j - k

Rishabh Mittal · Accepted Answer

Let A→=2i^+ j^-4k^  and  B→=3i^+j^-k^Unit vector peroendicular to the vectors A→ and B→ = A→× B→ A→× B→  A→× B→ =i^ j^k^21-431-1=-1+4i^--2+12 j^+2-3k^            =3i^-10j^-k^A→× B→ =3i^-10j^-k^=32+-102+-12             =9+100+1=110So, Unit vector perpendicular to the vectors A→ and B→ and of magnitude 1 unit =3i^-10j^-k^110=3110i^-10110j^-1110k^Therefore scalar components of vector are: 3110,-10110,-1110

Calculate the components of a vector of magnitude unity which is at right angles to the vectors 2i + j - 4k and 3i + j - k